Atherosclerosis and Lipoproteins |
From the Second Department of Internal Medicine (X.P.Y., A.I., K.Y., K.K., H.M.), Department of General Medicine (J.K.), School of Medicine, Kanazawa University, Takara-machi 13-1 Kanazawa, Ishikawa 920-8641, Japan.
| Abstract |
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Key Words: abetalipoproteinemia microsomal triglyceride transfer protein mitotic recombination splicing mutation uniparental disomy
| Introduction |
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In contrast to classical Mendelian inheritance, uniparental disomy (UPD) is the inheritance of 2 copies of a region of chromosome from only one parent, without any contribution from the second parent. Inheritance of a pair of homologous chromosomes from one parent is uniparental heterodisomy. Inheritance of 2 copies of a single chromosome homolog from one parent is defined as uniparental isodisomy.10 11 UPD may be associated with either an abnormal or a normal phenotype.12 UPD case reports may provide a clue to study of human genomic imprinting,12 13 an important mechanism of gene regulation.14 Isodisomy may result in a higher risk of autosomal recessive disorder than would heterodisomy.
We report here the first case of MTP deficiency caused by maternal UPD. The patient is homozygous for an intron 9 splicing mutation. He inherited 2 identical mutant alleles from his mother via maternal isodisomy of chromosome 4q. The MTP gene maps to 4q.4 8 Even though UPD has been documented for 17 human autosomes and the X and Y chromosomes, resulting in 18 recessive diseases, including LPL deficiency,12 15 only 1 case of isochromosome 4 (46, -4, -4, +i4q, +i4p) has been reported.16 In both cases of UPD4, phenotype did not suggest any abnormalities due to imprinting.
| Methods |
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Serum Chemistry Analyses
Serum cholesterol and triglyceride
concentrations were measured by enzymatic methods.17 18
HDL cholesterol (HDL-C) was determined by a heparin-calcium
chloride precipitation method.19 Apolipoprotein levels
were measured by immunoturbidimetry.20 Vitamin A and K
levels were determined by high-performance liquid
chromatography21 22 ; Vitamin E level was
determined fluorometrically.23
Mutation Analysis
From the total RNA extracted from proband's jejunal biopsy
specimen, a full-length MTP cDNA was obtained through reverse
transcriptase-polymerase chain reaction (SuperScript, BRL
Gibco) using a pair of primers based on published cDNA
sequence.4 The product was subcloned into a Bluescript
vector. Wild type pRC/hMTP cDNA was kindly provided by Dr John R.
Wetterau (Bristol-Myers Squibb, Department of Metabolic
Diseases, Princeton, NJ), and used as the control cDNA
sequence. Genomic DNA was extracted from peripheral blood
leukocytes by a phenol-chloroform method and used for DNA sequence
analyses. Sequencing was performed with either an ABI PRISM dye
terminator cycle sequencing ready reaction kit (PE Applied Biosystems)
or a nonradioisotopic DNA sequencing kit (Sequencing High and Imaging
High, Toyobo). PCR was used to amplify exon 10 and adjacent regions
using a pair of primers based on published MTP gene
sequences.6 For polymerase chain reaction-restriction
fragment length polymorphism (PCR-RFLP) analysis, a
fragment of the junction of intron 9 and exon 10 was amplified by PCR
using an intron 9 forward primer, 5'-AGAATTCCCTGTACCACAGGT-3', and a
mismatch reverse primer of 5'-CCAATAGAACCTTTGAACTgACT-3'. The 250
base pair fragment was digested with Hinf I, loaded on to a 10%
acrylamide gel for electrophoresis, and visualized with
ethidium bromide.
Testing for UPD
Short tandem repeat (STR) markers for chromosome 4 were
obtained from the Cooperative Human Linkage Center (http://www.chlc.
org/). STR fragments were amplified using genomic DNA as a template and
pairs of primers, with one primer of each pair being labeled with
fluorescein isothiocyanate. After denaturing at 95°C, the
amplified fragments were loaded on a denaturing polyacrylamide
gel and detected using Genescan software (PE Applied Biosystems).
Paternity testing was performed using 3 STR markers from 3 different chromosomes (chromosomes 5, 7, and 13; Geneprint Fluorescent STR System, Promega, Madison, WI), apo E polymorphism (chromosome 19), and 2 specific Y chromosome markers. The analysis was based on the published gene frequencies for general Japanese populations,24 25 26 using PT-TRIO software to calculate the probability of paternity between the proband and his father.27
Cytogenetic Analysis
Karyotypings, G-banding and high resolutional analyses,
were performed on cultured blood lymphocytes from the proband.
| Results |
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MTP Gene Analyses
Compared with the wild-type sequence, the proband's MTP
cDNA has a deletion of 36 consecutive amino acids encoded by exon 10
(Figure 1
). This deletion is expected to
result in a complete deficiency of MTP activity. Direct sequencing of
exon 10 and the junction of intron 9 and exon 10 showed a G-to-A
transition at the splice acceptor site (-1) in the proband MTP gene
(Figure 2
). The proband had an additional
G to T transversion in the intron 9 splice position (-7). The proband
was homozygous for the intron 9 splice G(-1)-to-A mutation;
his mother, with 1 normal base G and 1 mutant base A, was a
heterozygote, whereas his father was homozygous for the normal base
G. PCR-RFLP analysis was used to confirm this mutation
using Hinf I digestion. The junction of intron 9 and exon 10 of MTP
gene was amplified with a pair of primers. The mismatch primer created
a Hinf I restriction site in the normal sequence, which is lost in the
mutant sequence because of the G-to-A transition. Digestion of the PCR
products with Hinf I resulted in either a 230 bp wild-type sized
fragment or a 250 bp mutant-sized fragment. The proband produced a
single 250 bp mutant-sized fragment. His mother, a sister, and his
maternal grandfather produced 2 fragments, both the 230 bp wild-type
and the 250 bp mutant fragment, indicating heterozygotes. A partial
pedigree of this family for MTP deficiency is shown in Figure 3
. His father was proven to be homozygous
for the wild-type allele of the mutation site, despite a presumed
obligate heterozygote. This result indicates that the proband inherited
the recessive MTP mutation only from his mother.
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Maternal Isodisomy of Chromosome 4q21-35
The MTP gene has been mapped to chromosome
4q22-24.4 8 The proband's karyotype was normal by
G-banding, and high-resolution analyses of 4 pairs of
chromosome 4 revealed no obvious deletion. As the mutation from the
proband's mother was inherited from her father and the mutation was
absent in the paternal branch of the proband's family (Figure 3
), we propose that maternal disomy for chromosome 4 is
responsible for the homozygosity of the mutant MTP gene that results in
ABL in this patient. UPD testing was carried out with STR markers on
chromosome 4, as shown in Figure 4
and
Table 2
. The informative markers D4S1647, GAGT62A12, D4S2392,
D4S2395, D4S2378, D4S2428, D4S2368, and D4S2417 show that the proband
possesses only the mother's alleles in the chromosome region
4q21-35. The father's alleles are absent from the proband in this
region. All the markers showed reduction to homozygosity over 150
centimorgans in the proband's chromosome 4q. However, the proband
inherited biparental alleles in 4 of polymorphic markers (vWFA,
TPOX, THO1, and Apo E) from different chromosomes of 5, 7, 13, and 19.
He is also a biparental heterozygote for the 4p and centromeric markers
of D4S2633 and D4S2379 (Table 2
). Results from STR markers from
4p16-q13 indicate that this region was inherited biparentally, and UPD
was not via maternal heterodisomy.
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Paternity testing, including analyses of 4 markers of autosomes and markers of YAP and DYS19 in chromosome Y, indicated a paternity probability of 0.999 between the proband and his father.
| Discussion |
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Four splice donor site mutations have been reported in patients with homozygous MTP deficiency, so far. These patients were diagnosed in infancy. They took large doses vitamin E, and neurological findings were not remarkable.5 8 29 30 Our patient had a splice acceptor mutation, but was diagnosed in his late 20's, and presented a prominent neurological syndrome. The serious neurological symptoms may have resulted from long-term vitamin E deficiency. Alternatively, the proband may have another recessive disease with deteriorating neurological symptoms due to the maternal isodisomy.
UPD can result from one of several mechanisms10 11 31 32 33 34 35 :
(1) Fertilization of a nullisomic by a disomic gamete, (2)
chromosome duplication in a monosomic somatic cell after a postzygotic
loss of one homologous chromosome (ie, monosomy rescue), (3) loss of a
supernumerary chromosome in a cell with aneuploidy (ie, trisomy
rescue), and (4) mitotic recombination in somatic cells that results in
UPD for a portion of a chromosome (partial UPD). The mechanisms of
monosomy or trisomy rescue result in complete UPD, whereas somatic
recombination results in partial UPD. Because a paternal contribution
to chromosome 4, from 4p to the centromere, of the proband was
indicated by 2 informative markers (Table 2
), mitotic
recombination at an early division between 4q13 and 4q21 appeared to be
a plausible mechanism for this case, as shown in some cases of
Beckwith-Wiedemann syndrome (paternal UPD 11p).34 35
Although some cases of Bechwith-Wiedemann syndrome are somatic mosaics,
this was not evident in our proband. No wild-type MTP cDNA was obtained
from jejunum RNA, and there were no additional DNA fragments seen in
the STR marker analyses using genomic DNA from
peripheral blood cells (Figure 4
). Also, the severe
phenotype of this case of ABL is inconsisient with mosaicism of
chromosome 4q isodisomy.
UPD is calculated to occur in 2.8 of 10 000 conceptions.10 UPD as the cause of an abnormal phenotype should be considered, when a rare recessive disease is diagnosed without consanguinity. Many UPD cases are associated with specific syndromes or growth retardation, resulting from imprinting genes or loci. In cases of Prader-Willi syndrome (PWS), the reported frequency of maternal disomy is 25% and that of paternal deletion is 75%,13 which indicated that loss of paternal genetic material caused PWS. Previous reports of UPD expressing the recessive cystic fibrosis gene with short stature have indicated genomic imprinting in chromosome 7.31 36 37 The human chromosome 4 region has been reported to be homologous to a portion of mouse chromosome 3 that is not implicated in parent of origin differences.38 As only a report of UPD4, a woman with multiple early miscarriages had maternal isochromosome 4p and 4q.16 She was the tallest among her siblings but was otherwise normal. Our proband appeared normal except for manifestations of ABL, including small stature and low body weight. As compared with 3 Japanese male patients with ABL reported. our proband's birth weight 3200 g was not different from 2780±630 g [SD], but height 152 cm and weight 45 kg at our proband's age of 29 years were somewhat smaller than 164±13 cm and 56±14 kg at their mean age of 26±8 years, respectively. Thus, we believe that there are no obvious phenotypic effects of the UPD on our proband, but some effect on growth failure cannot be ruled out. In addition, we could not exclude the possibility that some region of chromosome 4 could be paternally inactivated, because no case of paternal UPD of chromosome 4 has been reported to date.
In conclusion, we determined that the proband in our study suffered from ABL that resulted from a homozygous mutation of the MTP gene. The proband was homozyous for the MTP mutant allele because of maternal UPD 4q21-35 region probably caused by mitotic recombination. This case study may provide a clue to explain phenotypic variability among ABL patients.
| Acknowledgments |
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| Footnotes |
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Received October 14, 1998; accepted December 29, 1998.
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